# Probability Calculations For A Number Of Events

Appendix E of AGS (2000) details the equations for calculation of the probability of a rock falling onto a moving vehicle. It is useful for those of us with a shaky understanding of the detail of probability calculations to consider how equation E1 of Appendix E can be derived as this fundamental concept can be applied to other cases.

For simplicity, consider the probability of throwing a six with a normal cubic die. Since there are six possible outcomes, the probability is 1 in 6 (1/6).

What then is the probability of throwing a six in any one or more of ten throws of the die?

- It can not be 10 times (1/6) since that is greater than 1.0 which is impossible.
- It is not (1/6)
^{10}since that is the probability of throwing a six on each of ten throws. - Consider what the possible outcomes for the ten throws would be in terms of the number of sixes:

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, or 10 sixes

All except 0 sixes satisfy the requirement of a six on one or more throws.

The probability of not getting a six on a single throw is (5/6). This can also be derived as (1 – Probability of a six).

Then the probability of 0 sixes in ten throws is (5/6)^{10}.

The numerical total of the probability of each of the possible outcomes must be 1. That is (Probability of 0 sixes + Probability of one or more sixes) = 1

Therefore, the Probability of 1 or more sixes = (1- (5/6)^{10})

Expressing this algebraically, if

P_{(6)} = Probability of throwing a six

N = Number of throws

Then

P_{(6:10)} = 1- (1 – P_{(6)})^{N}

This is in effect Equation E1.